Python从矩阵过滤代表字典键的不可变行

本文概述

• Python3
• Python3

给定矩阵, 提取所有包含元素的行, 这些行具有可以表示为字典键(即不可变)的所有元素。

输入：test_list = [[4, 5, [2, 3, 2]], [“gfg”, 1, (4, 4)], [{5:4}, 3, “good”], [True, “best”]]
输出：[[‘gfg’, 1, (4, 4)], [True, ‘best’]]
说明：元组中的所有元素都是不可变的。
输入：test_list = [[4, 5, [2, 3, 2]], [” gfg”, 1, (4, 4), [3, 2]], [{5：4}, 3, “好”], [True, “good”]]
输出：[[True, ‘best’]]
说明：元组中的所有元素都是不可变的。

方法1：使用all()+ isinstance()

在此, 我们检查所有元素是否都是不可变数据类型的实例, 返回的行true对于所有元素, 将被过滤。

Python3

# Python3 code to demonstrate working of
# Filter Dictionary Key Possible Element rows
# Using all() + isinstance()
  
# initializing list
test_list = [[ 4 , 5 , [ 2 , 3 , 2 ]], [ "gfg" , 1 , ( 4 , 4 )], [{ 5 : 4 }, 3 , "good" ], [
     True , "best" ]]
  
# printing original list
print ( "The original list is : " + str (test_list))
  
# checking for each immutable data type
res = [row for row in test_list if all ( isinstance (ele, int ) or isinstance (ele, bool )
                                        or isinstance (ele, float ) or isinstance (ele, tuple )
                                        or isinstance (ele, str ) for ele in row)]
  
# printing result
print ( "Filtered rows : " + str (res))

输出如下：

原始列表是：[[4, 5, [2, 3, 2]], [‘gfg’, 1, (4, 4)], [{5：4}, 3, ‘good’], [True , ‘best’]]
过滤的行：[[‘gfg’, 1, (4, 4)], [True, ‘good’]]

方法2：使用filter()+ lambda + isinstance()+ all()

在此, 我们使用filter()+ lambda功能, 其余所有功能均按上述方法执行。

Python3

# Python3 code to demonstrate working of
# Filter Dictionary Key Possible Element rows
# Using filter() + lambda + isinstance() + all()
  
# initializing list
test_list = [[ 4 , 5 , [ 2 , 3 , 2 ]], [ "gfg" , 1 , ( 4 , 4 )], [{ 5 : 4 }, 3 , "good" ], [
     True , "best" ]]
  
# printing original list
print ( "The original list is : " + str (test_list))
  
# checking for each immutable data type
# filtering using filter()
res = list ( filter ( lambda row: all ( isinstance (ele, int ) or isinstance (ele, bool )
                                   or isinstance (ele, float ) or isinstance (ele, tuple )
                                   or isinstance (ele, str ) for ele in row), test_list))
  
# printing result
print ( "Filtered rows : " + str (res))

输出如下：

原始列表是：[[4, 5, [2, 3, 2]], [‘gfg’, 1, (4, 4)], [{5：4}, 3, ‘good’], [True , ‘best’]]
过滤的行：[[‘gfg’, 1, (4, 4)], [True, ‘good’]]

首先, 你的面试准备可通过以下方式增强你的数据结构概念：Python DS课程。