numpy hypot()方法示例

``h = sqrt(b**2 + p**2)``

h的每个值都将复制到输出数组中。

句法

``numpy.hypot(array1, array2 out)``

参数

1. array1：它是给定直角三角形的底边的输入数组。
2. array2：它是给定直角三角形的垂直线的输入数组。
3. Out：这是输出数组的形状。

例子1

``````import numpy as np

base = [10, 2, 5, 50]
per= [3, 10, 23, 6]

print("Input base array:", base)
print("Input perpendicular array:", per)

hyp = np.hypot(base, per)

print("hypotenuse ", hyp)``````

``````Input base array: [10, 2, 5, 50]
Input perpendicular array: [3, 10, 23, 6]
hypotenuse  [10.44030651 10.19803903 23.53720459 50.35871325]``````

例子2

``````import numpy as np

base = np.random.rand(3, 4)
per= np.random.rand(3, 4)

print("Input base array:", base)
print("Input perpendicular array:", per)

hyp = np.hypot(base, per)

print("hypotenuse ", hyp)``````

``````Input base array: [[0.38040712 0.8629511  0.5018026  0.08201071]
[0.77464952 0.68392036 0.10326945 0.69031164]
[0.35380139 0.58803283 0.19791751 0.48756617]]

Input perpendicular array: [[0.50466085 0.38053395 0.96808322 0.69790711]
[0.77802303 0.5486305  0.34418331 0.69201998]
[0.28038631 0.35850426 0.90459831 0.13383838]]

hypotenuse  [[0.63197481 0.94312814 1.09040862 0.70270911]
[1.09790788 0.87677961 0.35934208 0.97745681]
[0.45143318 0.68870017 0.92599646 0.5056021 ]]``````